3.11.3 \(\int \frac {(A+B x) (a+b x+c x^2)^3}{\sqrt {x}} \, dx\) [1003]

3.11.3.1 Optimal result
3.11.3.2 Mathematica [A] (verified)
3.11.3.3 Rubi [A] (verified)
3.11.3.4 Maple [A] (verified)
3.11.3.5 Fricas [A] (verification not implemented)
3.11.3.6 Sympy [A] (verification not implemented)
3.11.3.7 Maxima [A] (verification not implemented)
3.11.3.8 Giac [A] (verification not implemented)
3.11.3.9 Mupad [B] (verification not implemented)

3.11.3.1 Optimal result

Integrand size = 23, antiderivative size = 180 \[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^3}{\sqrt {x}} \, dx=2 a^3 A \sqrt {x}+\frac {2}{3} a^2 (3 A b+a B) x^{3/2}+\frac {6}{5} a \left (a b B+A \left (b^2+a c\right )\right ) x^{5/2}+\frac {2}{7} \left (3 a B \left (b^2+a c\right )+A \left (b^3+6 a b c\right )\right ) x^{7/2}+\frac {2}{9} \left (b^3 B+3 A b^2 c+6 a b B c+3 a A c^2\right ) x^{9/2}+\frac {6}{11} c \left (b^2 B+A b c+a B c\right ) x^{11/2}+\frac {2}{13} c^2 (3 b B+A c) x^{13/2}+\frac {2}{15} B c^3 x^{15/2} \]

output
2/3*a^2*(3*A*b+B*a)*x^(3/2)+6/5*a*(a*b*B+A*(a*c+b^2))*x^(5/2)+2/7*(3*a*B*( 
a*c+b^2)+A*(6*a*b*c+b^3))*x^(7/2)+2/9*(3*A*a*c^2+3*A*b^2*c+6*B*a*b*c+B*b^3 
)*x^(9/2)+6/11*c*(A*b*c+B*a*c+B*b^2)*x^(11/2)+2/13*c^2*(A*c+3*B*b)*x^(13/2 
)+2/15*B*c^3*x^(15/2)+2*a^3*A*x^(1/2)
 
3.11.3.2 Mathematica [A] (verified)

Time = 0.13 (sec) , antiderivative size = 176, normalized size of antiderivative = 0.98 \[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^3}{\sqrt {x}} \, dx=\frac {2 \sqrt {x} \left (15015 a^3 (3 A+B x)+1287 a^2 x (7 A (5 b+3 c x)+3 B x (7 b+5 c x))+39 a x^2 \left (11 A \left (63 b^2+90 b c x+35 c^2 x^2\right )+5 B x \left (99 b^2+154 b c x+63 c^2 x^2\right )\right )+x^3 \left (15 A \left (429 b^3+1001 b^2 c x+819 b c^2 x^2+231 c^3 x^3\right )+7 B x \left (715 b^3+1755 b^2 c x+1485 b c^2 x^2+429 c^3 x^3\right )\right )\right )}{45045} \]

input
Integrate[((A + B*x)*(a + b*x + c*x^2)^3)/Sqrt[x],x]
 
output
(2*Sqrt[x]*(15015*a^3*(3*A + B*x) + 1287*a^2*x*(7*A*(5*b + 3*c*x) + 3*B*x* 
(7*b + 5*c*x)) + 39*a*x^2*(11*A*(63*b^2 + 90*b*c*x + 35*c^2*x^2) + 5*B*x*( 
99*b^2 + 154*b*c*x + 63*c^2*x^2)) + x^3*(15*A*(429*b^3 + 1001*b^2*c*x + 81 
9*b*c^2*x^2 + 231*c^3*x^3) + 7*B*x*(715*b^3 + 1755*b^2*c*x + 1485*b*c^2*x^ 
2 + 429*c^3*x^3))))/45045
 
3.11.3.3 Rubi [A] (verified)

Time = 0.32 (sec) , antiderivative size = 180, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {1195, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(A+B x) \left (a+b x+c x^2\right )^3}{\sqrt {x}} \, dx\)

\(\Big \downarrow \) 1195

\(\displaystyle \int \left (\frac {a^3 A}{\sqrt {x}}+a^2 \sqrt {x} (a B+3 A b)+3 c x^{9/2} \left (a B c+A b c+b^2 B\right )+3 a x^{3/2} \left (A \left (a c+b^2\right )+a b B\right )+x^{7/2} \left (3 a A c^2+6 a b B c+3 A b^2 c+b^3 B\right )+x^{5/2} \left (A \left (6 a b c+b^3\right )+3 a B \left (a c+b^2\right )\right )+c^2 x^{11/2} (A c+3 b B)+B c^3 x^{13/2}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle 2 a^3 A \sqrt {x}+\frac {2}{3} a^2 x^{3/2} (a B+3 A b)+\frac {6}{11} c x^{11/2} \left (a B c+A b c+b^2 B\right )+\frac {6}{5} a x^{5/2} \left (A \left (a c+b^2\right )+a b B\right )+\frac {2}{9} x^{9/2} \left (3 a A c^2+6 a b B c+3 A b^2 c+b^3 B\right )+\frac {2}{7} x^{7/2} \left (A \left (6 a b c+b^3\right )+3 a B \left (a c+b^2\right )\right )+\frac {2}{13} c^2 x^{13/2} (A c+3 b B)+\frac {2}{15} B c^3 x^{15/2}\)

input
Int[((A + B*x)*(a + b*x + c*x^2)^3)/Sqrt[x],x]
 
output
2*a^3*A*Sqrt[x] + (2*a^2*(3*A*b + a*B)*x^(3/2))/3 + (6*a*(a*b*B + A*(b^2 + 
 a*c))*x^(5/2))/5 + (2*(3*a*B*(b^2 + a*c) + A*(b^3 + 6*a*b*c))*x^(7/2))/7 
+ (2*(b^3*B + 3*A*b^2*c + 6*a*b*B*c + 3*a*A*c^2)*x^(9/2))/9 + (6*c*(b^2*B 
+ A*b*c + a*B*c)*x^(11/2))/11 + (2*c^2*(3*b*B + A*c)*x^(13/2))/13 + (2*B*c 
^3*x^(15/2))/15
 

3.11.3.3.1 Defintions of rubi rules used

rule 1195
Int[((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))^(n_.)*((a_.) + (b_.)*(x 
_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[(d + e*x)^m*(f + 
 g*x)^n*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, f, g, m, n}, x 
] && IGtQ[p, 0]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 
3.11.3.4 Maple [A] (verified)

Time = 0.29 (sec) , antiderivative size = 191, normalized size of antiderivative = 1.06

method result size
trager \(\left (\frac {2}{15} B \,c^{3} x^{7}+\frac {2}{13} A \,c^{3} x^{6}+\frac {6}{13} B b \,c^{2} x^{6}+\frac {6}{11} A b \,c^{2} x^{5}+\frac {6}{11} a B \,c^{2} x^{5}+\frac {6}{11} B \,b^{2} c \,x^{5}+\frac {2}{3} a A \,c^{2} x^{4}+\frac {2}{3} A \,b^{2} c \,x^{4}+\frac {4}{3} B a b c \,x^{4}+\frac {2}{9} x^{4} B \,b^{3}+\frac {12}{7} A a b c \,x^{3}+\frac {2}{7} A \,b^{3} x^{3}+\frac {6}{7} a^{2} B c \,x^{3}+\frac {6}{7} B a \,b^{2} x^{3}+\frac {6}{5} a^{2} A c \,x^{2}+\frac {6}{5} A a \,b^{2} x^{2}+\frac {6}{5} B \,a^{2} b \,x^{2}+2 A \,a^{2} b x +\frac {2}{3} a^{3} B x +2 A \,a^{3}\right ) \sqrt {x}\) \(191\)
gosper \(\frac {2 \sqrt {x}\, \left (3003 B \,c^{3} x^{7}+3465 A \,c^{3} x^{6}+10395 B b \,c^{2} x^{6}+12285 A b \,c^{2} x^{5}+12285 a B \,c^{2} x^{5}+12285 B \,b^{2} c \,x^{5}+15015 a A \,c^{2} x^{4}+15015 A \,b^{2} c \,x^{4}+30030 B a b c \,x^{4}+5005 x^{4} B \,b^{3}+38610 A a b c \,x^{3}+6435 A \,b^{3} x^{3}+19305 a^{2} B c \,x^{3}+19305 B a \,b^{2} x^{3}+27027 a^{2} A c \,x^{2}+27027 A a \,b^{2} x^{2}+27027 B \,a^{2} b \,x^{2}+45045 A \,a^{2} b x +15015 a^{3} B x +45045 A \,a^{3}\right )}{45045}\) \(192\)
risch \(\frac {2 \sqrt {x}\, \left (3003 B \,c^{3} x^{7}+3465 A \,c^{3} x^{6}+10395 B b \,c^{2} x^{6}+12285 A b \,c^{2} x^{5}+12285 a B \,c^{2} x^{5}+12285 B \,b^{2} c \,x^{5}+15015 a A \,c^{2} x^{4}+15015 A \,b^{2} c \,x^{4}+30030 B a b c \,x^{4}+5005 x^{4} B \,b^{3}+38610 A a b c \,x^{3}+6435 A \,b^{3} x^{3}+19305 a^{2} B c \,x^{3}+19305 B a \,b^{2} x^{3}+27027 a^{2} A c \,x^{2}+27027 A a \,b^{2} x^{2}+27027 B \,a^{2} b \,x^{2}+45045 A \,a^{2} b x +15015 a^{3} B x +45045 A \,a^{3}\right )}{45045}\) \(192\)
derivativedivides \(\frac {2 B \,c^{3} x^{\frac {15}{2}}}{15}+\frac {2 \left (A \,c^{3}+3 B b \,c^{2}\right ) x^{\frac {13}{2}}}{13}+\frac {2 \left (3 A b \,c^{2}+B \left (a \,c^{2}+2 b^{2} c +c \left (2 a c +b^{2}\right )\right )\right ) x^{\frac {11}{2}}}{11}+\frac {2 \left (A \left (a \,c^{2}+2 b^{2} c +c \left (2 a c +b^{2}\right )\right )+B \left (4 a b c +b \left (2 a c +b^{2}\right )\right )\right ) x^{\frac {9}{2}}}{9}+\frac {2 \left (A \left (4 a b c +b \left (2 a c +b^{2}\right )\right )+B \left (a \left (2 a c +b^{2}\right )+2 b^{2} a +c \,a^{2}\right )\right ) x^{\frac {7}{2}}}{7}+\frac {2 \left (A \left (a \left (2 a c +b^{2}\right )+2 b^{2} a +c \,a^{2}\right )+3 B b \,a^{2}\right ) x^{\frac {5}{2}}}{5}+\frac {2 \left (3 A \,a^{2} b +B \,a^{3}\right ) x^{\frac {3}{2}}}{3}+2 a^{3} A \sqrt {x}\) \(226\)
default \(\frac {2 B \,c^{3} x^{\frac {15}{2}}}{15}+\frac {2 \left (A \,c^{3}+3 B b \,c^{2}\right ) x^{\frac {13}{2}}}{13}+\frac {2 \left (3 A b \,c^{2}+B \left (a \,c^{2}+2 b^{2} c +c \left (2 a c +b^{2}\right )\right )\right ) x^{\frac {11}{2}}}{11}+\frac {2 \left (A \left (a \,c^{2}+2 b^{2} c +c \left (2 a c +b^{2}\right )\right )+B \left (4 a b c +b \left (2 a c +b^{2}\right )\right )\right ) x^{\frac {9}{2}}}{9}+\frac {2 \left (A \left (4 a b c +b \left (2 a c +b^{2}\right )\right )+B \left (a \left (2 a c +b^{2}\right )+2 b^{2} a +c \,a^{2}\right )\right ) x^{\frac {7}{2}}}{7}+\frac {2 \left (A \left (a \left (2 a c +b^{2}\right )+2 b^{2} a +c \,a^{2}\right )+3 B b \,a^{2}\right ) x^{\frac {5}{2}}}{5}+\frac {2 \left (3 A \,a^{2} b +B \,a^{3}\right ) x^{\frac {3}{2}}}{3}+2 a^{3} A \sqrt {x}\) \(226\)

input
int((B*x+A)*(c*x^2+b*x+a)^3/x^(1/2),x,method=_RETURNVERBOSE)
 
output
(2/15*B*c^3*x^7+2/13*A*c^3*x^6+6/13*B*b*c^2*x^6+6/11*A*b*c^2*x^5+6/11*a*B* 
c^2*x^5+6/11*B*b^2*c*x^5+2/3*a*A*c^2*x^4+2/3*A*b^2*c*x^4+4/3*B*a*b*c*x^4+2 
/9*x^4*B*b^3+12/7*A*a*b*c*x^3+2/7*A*b^3*x^3+6/7*a^2*B*c*x^3+6/7*B*a*b^2*x^ 
3+6/5*a^2*A*c*x^2+6/5*A*a*b^2*x^2+6/5*B*a^2*b*x^2+2*A*a^2*b*x+2/3*a^3*B*x+ 
2*A*a^3)*x^(1/2)
 
3.11.3.5 Fricas [A] (verification not implemented)

Time = 0.29 (sec) , antiderivative size = 166, normalized size of antiderivative = 0.92 \[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^3}{\sqrt {x}} \, dx=\frac {2}{45045} \, {\left (3003 \, B c^{3} x^{7} + 3465 \, {\left (3 \, B b c^{2} + A c^{3}\right )} x^{6} + 12285 \, {\left (B b^{2} c + {\left (B a + A b\right )} c^{2}\right )} x^{5} + 5005 \, {\left (B b^{3} + 3 \, A a c^{2} + 3 \, {\left (2 \, B a b + A b^{2}\right )} c\right )} x^{4} + 45045 \, A a^{3} + 6435 \, {\left (3 \, B a b^{2} + A b^{3} + 3 \, {\left (B a^{2} + 2 \, A a b\right )} c\right )} x^{3} + 27027 \, {\left (B a^{2} b + A a b^{2} + A a^{2} c\right )} x^{2} + 15015 \, {\left (B a^{3} + 3 \, A a^{2} b\right )} x\right )} \sqrt {x} \]

input
integrate((B*x+A)*(c*x^2+b*x+a)^3/x^(1/2),x, algorithm="fricas")
 
output
2/45045*(3003*B*c^3*x^7 + 3465*(3*B*b*c^2 + A*c^3)*x^6 + 12285*(B*b^2*c + 
(B*a + A*b)*c^2)*x^5 + 5005*(B*b^3 + 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*c)*x^ 
4 + 45045*A*a^3 + 6435*(3*B*a*b^2 + A*b^3 + 3*(B*a^2 + 2*A*a*b)*c)*x^3 + 2 
7027*(B*a^2*b + A*a*b^2 + A*a^2*c)*x^2 + 15015*(B*a^3 + 3*A*a^2*b)*x)*sqrt 
(x)
 
3.11.3.6 Sympy [A] (verification not implemented)

Time = 0.33 (sec) , antiderivative size = 291, normalized size of antiderivative = 1.62 \[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^3}{\sqrt {x}} \, dx=2 A a^{3} \sqrt {x} + 2 A a^{2} b x^{\frac {3}{2}} + \frac {6 A a^{2} c x^{\frac {5}{2}}}{5} + \frac {6 A a b^{2} x^{\frac {5}{2}}}{5} + \frac {12 A a b c x^{\frac {7}{2}}}{7} + \frac {2 A a c^{2} x^{\frac {9}{2}}}{3} + \frac {2 A b^{3} x^{\frac {7}{2}}}{7} + \frac {2 A b^{2} c x^{\frac {9}{2}}}{3} + \frac {6 A b c^{2} x^{\frac {11}{2}}}{11} + \frac {2 A c^{3} x^{\frac {13}{2}}}{13} + \frac {2 B a^{3} x^{\frac {3}{2}}}{3} + \frac {6 B a^{2} b x^{\frac {5}{2}}}{5} + \frac {6 B a^{2} c x^{\frac {7}{2}}}{7} + \frac {6 B a b^{2} x^{\frac {7}{2}}}{7} + \frac {4 B a b c x^{\frac {9}{2}}}{3} + \frac {6 B a c^{2} x^{\frac {11}{2}}}{11} + \frac {2 B b^{3} x^{\frac {9}{2}}}{9} + \frac {6 B b^{2} c x^{\frac {11}{2}}}{11} + \frac {6 B b c^{2} x^{\frac {13}{2}}}{13} + \frac {2 B c^{3} x^{\frac {15}{2}}}{15} \]

input
integrate((B*x+A)*(c*x**2+b*x+a)**3/x**(1/2),x)
 
output
2*A*a**3*sqrt(x) + 2*A*a**2*b*x**(3/2) + 6*A*a**2*c*x**(5/2)/5 + 6*A*a*b** 
2*x**(5/2)/5 + 12*A*a*b*c*x**(7/2)/7 + 2*A*a*c**2*x**(9/2)/3 + 2*A*b**3*x* 
*(7/2)/7 + 2*A*b**2*c*x**(9/2)/3 + 6*A*b*c**2*x**(11/2)/11 + 2*A*c**3*x**( 
13/2)/13 + 2*B*a**3*x**(3/2)/3 + 6*B*a**2*b*x**(5/2)/5 + 6*B*a**2*c*x**(7/ 
2)/7 + 6*B*a*b**2*x**(7/2)/7 + 4*B*a*b*c*x**(9/2)/3 + 6*B*a*c**2*x**(11/2) 
/11 + 2*B*b**3*x**(9/2)/9 + 6*B*b**2*c*x**(11/2)/11 + 6*B*b*c**2*x**(13/2) 
/13 + 2*B*c**3*x**(15/2)/15
 
3.11.3.7 Maxima [A] (verification not implemented)

Time = 0.19 (sec) , antiderivative size = 166, normalized size of antiderivative = 0.92 \[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^3}{\sqrt {x}} \, dx=\frac {2}{15} \, B c^{3} x^{\frac {15}{2}} + \frac {2}{13} \, {\left (3 \, B b c^{2} + A c^{3}\right )} x^{\frac {13}{2}} + \frac {6}{11} \, {\left (B b^{2} c + {\left (B a + A b\right )} c^{2}\right )} x^{\frac {11}{2}} + \frac {2}{9} \, {\left (B b^{3} + 3 \, A a c^{2} + 3 \, {\left (2 \, B a b + A b^{2}\right )} c\right )} x^{\frac {9}{2}} + 2 \, A a^{3} \sqrt {x} + \frac {2}{7} \, {\left (3 \, B a b^{2} + A b^{3} + 3 \, {\left (B a^{2} + 2 \, A a b\right )} c\right )} x^{\frac {7}{2}} + \frac {6}{5} \, {\left (B a^{2} b + A a b^{2} + A a^{2} c\right )} x^{\frac {5}{2}} + \frac {2}{3} \, {\left (B a^{3} + 3 \, A a^{2} b\right )} x^{\frac {3}{2}} \]

input
integrate((B*x+A)*(c*x^2+b*x+a)^3/x^(1/2),x, algorithm="maxima")
 
output
2/15*B*c^3*x^(15/2) + 2/13*(3*B*b*c^2 + A*c^3)*x^(13/2) + 6/11*(B*b^2*c + 
(B*a + A*b)*c^2)*x^(11/2) + 2/9*(B*b^3 + 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*c 
)*x^(9/2) + 2*A*a^3*sqrt(x) + 2/7*(3*B*a*b^2 + A*b^3 + 3*(B*a^2 + 2*A*a*b) 
*c)*x^(7/2) + 6/5*(B*a^2*b + A*a*b^2 + A*a^2*c)*x^(5/2) + 2/3*(B*a^3 + 3*A 
*a^2*b)*x^(3/2)
 
3.11.3.8 Giac [A] (verification not implemented)

Time = 0.27 (sec) , antiderivative size = 193, normalized size of antiderivative = 1.07 \[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^3}{\sqrt {x}} \, dx=\frac {2}{15} \, B c^{3} x^{\frac {15}{2}} + \frac {6}{13} \, B b c^{2} x^{\frac {13}{2}} + \frac {2}{13} \, A c^{3} x^{\frac {13}{2}} + \frac {6}{11} \, B b^{2} c x^{\frac {11}{2}} + \frac {6}{11} \, B a c^{2} x^{\frac {11}{2}} + \frac {6}{11} \, A b c^{2} x^{\frac {11}{2}} + \frac {2}{9} \, B b^{3} x^{\frac {9}{2}} + \frac {4}{3} \, B a b c x^{\frac {9}{2}} + \frac {2}{3} \, A b^{2} c x^{\frac {9}{2}} + \frac {2}{3} \, A a c^{2} x^{\frac {9}{2}} + \frac {6}{7} \, B a b^{2} x^{\frac {7}{2}} + \frac {2}{7} \, A b^{3} x^{\frac {7}{2}} + \frac {6}{7} \, B a^{2} c x^{\frac {7}{2}} + \frac {12}{7} \, A a b c x^{\frac {7}{2}} + \frac {6}{5} \, B a^{2} b x^{\frac {5}{2}} + \frac {6}{5} \, A a b^{2} x^{\frac {5}{2}} + \frac {6}{5} \, A a^{2} c x^{\frac {5}{2}} + \frac {2}{3} \, B a^{3} x^{\frac {3}{2}} + 2 \, A a^{2} b x^{\frac {3}{2}} + 2 \, A a^{3} \sqrt {x} \]

input
integrate((B*x+A)*(c*x^2+b*x+a)^3/x^(1/2),x, algorithm="giac")
 
output
2/15*B*c^3*x^(15/2) + 6/13*B*b*c^2*x^(13/2) + 2/13*A*c^3*x^(13/2) + 6/11*B 
*b^2*c*x^(11/2) + 6/11*B*a*c^2*x^(11/2) + 6/11*A*b*c^2*x^(11/2) + 2/9*B*b^ 
3*x^(9/2) + 4/3*B*a*b*c*x^(9/2) + 2/3*A*b^2*c*x^(9/2) + 2/3*A*a*c^2*x^(9/2 
) + 6/7*B*a*b^2*x^(7/2) + 2/7*A*b^3*x^(7/2) + 6/7*B*a^2*c*x^(7/2) + 12/7*A 
*a*b*c*x^(7/2) + 6/5*B*a^2*b*x^(5/2) + 6/5*A*a*b^2*x^(5/2) + 6/5*A*a^2*c*x 
^(5/2) + 2/3*B*a^3*x^(3/2) + 2*A*a^2*b*x^(3/2) + 2*A*a^3*sqrt(x)
 
3.11.3.9 Mupad [B] (verification not implemented)

Time = 0.05 (sec) , antiderivative size = 169, normalized size of antiderivative = 0.94 \[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^3}{\sqrt {x}} \, dx=x^{7/2}\,\left (\frac {6\,B\,c\,a^2}{7}+\frac {6\,B\,a\,b^2}{7}+\frac {12\,A\,c\,a\,b}{7}+\frac {2\,A\,b^3}{7}\right )+x^{9/2}\,\left (\frac {2\,B\,b^3}{9}+\frac {2\,A\,b^2\,c}{3}+\frac {4\,B\,a\,b\,c}{3}+\frac {2\,A\,a\,c^2}{3}\right )+x^{3/2}\,\left (\frac {2\,B\,a^3}{3}+2\,A\,b\,a^2\right )+x^{13/2}\,\left (\frac {2\,A\,c^3}{13}+\frac {6\,B\,b\,c^2}{13}\right )+x^{5/2}\,\left (\frac {6\,B\,a^2\,b}{5}+\frac {6\,A\,c\,a^2}{5}+\frac {6\,A\,a\,b^2}{5}\right )+x^{11/2}\,\left (\frac {6\,B\,b^2\,c}{11}+\frac {6\,A\,b\,c^2}{11}+\frac {6\,B\,a\,c^2}{11}\right )+2\,A\,a^3\,\sqrt {x}+\frac {2\,B\,c^3\,x^{15/2}}{15} \]

input
int(((A + B*x)*(a + b*x + c*x^2)^3)/x^(1/2),x)
 
output
x^(7/2)*((2*A*b^3)/7 + (6*B*a*b^2)/7 + (6*B*a^2*c)/7 + (12*A*a*b*c)/7) + x 
^(9/2)*((2*B*b^3)/9 + (2*A*a*c^2)/3 + (2*A*b^2*c)/3 + (4*B*a*b*c)/3) + x^( 
3/2)*((2*B*a^3)/3 + 2*A*a^2*b) + x^(13/2)*((2*A*c^3)/13 + (6*B*b*c^2)/13) 
+ x^(5/2)*((6*A*a*b^2)/5 + (6*A*a^2*c)/5 + (6*B*a^2*b)/5) + x^(11/2)*((6*A 
*b*c^2)/11 + (6*B*a*c^2)/11 + (6*B*b^2*c)/11) + 2*A*a^3*x^(1/2) + (2*B*c^3 
*x^(15/2))/15